FUNCTION PARAMETERS
In the previous post, we had a look at functions. We briefly discussed parameters, but only briefly. While parameters are very simple and straight forward to use, there are tricks which can make them a lot more powerful.
The first thing that we will take a look at, is the out and ref modifiers. C#, and other languages as well, differ between two parameters: "by value" and "by reference". The default in C# is "by value", which basically means that when you pass on a variable to a function call, you are actually sending a copy of the object, instead of a reference to it. This also means that you can make changes to the parameter from inside the function, without affecting the original object you passed as a parameter.
With the ref and the out keyword, we can change this behavior, so we pass along a reference to the object instead of its value.
THE REF MODIFIER
Consider the following example:
We create an integer, assign the number 20 to it, and then we use the AddFive() method, which should add 5 to the number. But does it? No. The value we assign to number inside the function, is never carried out of the function, because we have passed a copy of the number value instead of a reference to it. This is simply how C# works, and in a lot of cases, it's the preferred result. However, in this case, we actually wish to modify the number inside our function. Enter the ref keyword:
As you can see, all we've done is adding the ref keyword to the function declaration as well as the call to the function. If you run the program now, you will see that the value of number has now changed, once we return from the function call.
THE OUT MODIFIER
The out modifier works pretty much like the ref modifier. They both ensure that the parameter is passed by reference instead of by value, but they do come with two important differences: A value passed to a ref modifier has to be initialized before calling the method - this is not true for the out modifier, where you can use un-initialized values. On the other hand, you can't leave a function call with an out parameter, without assigning a value to it. Since you can pass in un-initialized values as an out parameter, you are not able to actually use an out parameter inside a function - you can only assign a new value to it.
Whether to use out or ref really depends on the situation, as you will realize once you start using them. Both are typically used to work around the issue of only being able to return one value from a function, with C#.
Using the out modifier is just like using the ref modifier, as shown above. Simply change the ref keyword to the out keyword.
THE PARAMS MODIFIER
So far, all of our functions have accepted a fixed amount of parameters. However, in some cases, you might need a function which takes an arbitrary number of parameters. This could of course be done by accepting an array or a list as a parameter, like this:
However, calling it would be a bit clumsy. In the shortest form, it would look like this:
It is acceptable, but it can be done even smarter, with the params keyword:
Calling it would then look like this:
Another advantage of using the params approach, is that you are allowed to pass zero parameters to it as well.
Functions with params can even take other parameters as well, as long as the parameter with the params keyword are the last one. Besides that, only one parameter using the params keyword can be used per function. Here is a last and more complete example:
No comments:
Post a Comment